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1040424503147 is a prime number
BaseRepresentation
bin11110010001111100010…
…00100000011101101011
310200110111222020221211022
433020332020200131223
5114021242133100042
62113544151523055
7135111455234231
oct17107610403553
93613458227738
101040424503147
11371272565487
1214978408948b
137715b28b6a3
14384dd156951
151c0e5651cd2
hexf23e22076b

1040424503147 has 2 divisors, whose sum is σ = 1040424503148. Its totient is φ = 1040424503146.

The previous prime is 1040424503123. The next prime is 1040424503177. The reversal of 1040424503147 is 7413054240401.

1040424503147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1040424503147 - 210 = 1040424502123 is a prime.

It is not a weakly prime, because it can be changed into another prime (1040424503177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520212251573 + 520212251574.

It is an arithmetic number, because the mean of its divisors is an integer number (520212251574).

Almost surely, 21040424503147 is an apocalyptic number.

1040424503147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040424503147 is an equidigital number, since it uses as much as digits as its factorization.

1040424503147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 53760, while the sum is 35.

Adding to 1040424503147 its reverse (7413054240401), we get a palindrome (8453478743548).

The spelling of 1040424503147 in words is "one trillion, forty billion, four hundred twenty-four million, five hundred three thousand, one hundred forty-seven".