10404433141 has 4 divisors (see below), whose sum is σ = 10410790572. Its totient is φ = 10398075712.

The previous prime is 10404433133. The next prime is 10404433147. The reversal of 10404433141 is 14133440401.

10404433141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4428370116 + 5976063025 = 66546^2 + 77305^2 .

It is a cyclic number.

It is not a de Polignac number, because 10404433141 - 2³ = 10404433133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10404433147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3176260 + ... + 3179533.

It is an arithmetic number, because the mean of its divisors is an integer number (2602697643).

Almost surely, 2^10404433141 is an apocalyptic number.

It is an amenable number.

10404433141 is a deficient number, since it is larger than the sum of its proper divisors (6357431).

10404433141 is an equidigital number, since it uses as much as digits as its factorization.

10404433141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6357430.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 10404433141 its reverse (14133440401), we get a palindrome (24537873542).

The spelling of 10404433141 in words is "ten billion, four hundred four million, four hundred thirty-three thousand, one hundred forty-one".