Base | Representation |
---|---|
bin | 110000011100111110… |
… | …1001000110001001011 |
3 | 100221120112100001120010 |
4 | 1200321331020301023 |
5 | 3201044143334430 |
6 | 115444533403003 |
7 | 10342331344362 |
oct | 1407175106113 |
9 | 327515301503 |
10 | 104051543115 |
11 | 40145424443 |
12 | 181ba799463 |
13 | 9a73009a30 |
14 | 50711907d9 |
15 | 2a8ec91cb0 |
hex | 1839f48c4b |
104051543115 has 64 divisors (see below), whose sum is σ = 183778035840. Its totient is φ = 49944330240.
The previous prime is 104051543111. The next prime is 104051543131. The reversal of 104051543115 is 511345150401.
It is not a de Polignac number, because 104051543115 - 22 = 104051543111 is a prime.
It is a super-2 number, since 2×1040515431152 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (104051543111) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 17018299 + ... + 17024411.
It is an arithmetic number, because the mean of its divisors is an integer number (2871531810).
Almost surely, 2104051543115 is an apocalyptic number.
104051543115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
104051543115 is a deficient number, since it is larger than the sum of its proper divisors (79726492725).
104051543115 is a wasteful number, since it uses less digits than its factorization.
104051543115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8304.
The product of its (nonzero) digits is 6000, while the sum is 30.
Adding to 104051543115 its reverse (511345150401), we get a palindrome (615396693516).
The spelling of 104051543115 in words is "one hundred four billion, fifty-one million, five hundred forty-three thousand, one hundred fifteen".
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