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1040542147 is a prime number
BaseRepresentation
bin111110000001010…
…110100111000011
32200111222000111001
4332001112213003
54112334322042
6251130232431
734533314401
oct7601264703
92614860431
101040542147
114943a4797
12250585717
13137763718
149c2a2471
156153dbb7
hex3e0569c3

1040542147 has 2 divisors, whose sum is σ = 1040542148. Its totient is φ = 1040542146.

The previous prime is 1040542141. The next prime is 1040542159. The reversal of 1040542147 is 7412450401.

1040542147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (7412450401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1040542147 - 211 = 1040540099 is a prime.

It is not a weakly prime, because it can be changed into another prime (1040542141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520271073 + 520271074.

It is an arithmetic number, because the mean of its divisors is an integer number (520271074).

Almost surely, 21040542147 is an apocalyptic number.

1040542147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040542147 is an equidigital number, since it uses as much as digits as its factorization.

1040542147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4480, while the sum is 28.

The square root of 1040542147 is about 32257.4355304324. The cubic root of 1040542147 is about 1013.3354249461.

Adding to 1040542147 its reverse (7412450401), we get a palindrome (8452992548).

The spelling of 1040542147 in words is "one billion, forty million, five hundred forty-two thousand, one hundred forty-seven".