1041000131 has 2 divisors, whose sum is σ = 1041000132. Its totient is φ = 1041000130.

The previous prime is 1041000113. The next prime is 1041000241. The reversal of 1041000131 is 1310001401.

1041000131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (1041000113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (1310001401) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1041000131 is a prime.

It is a super-2 number, since 2×1041000131² = 2167362545484034322, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1041000431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520500065 + 520500066.

It is an arithmetic number, because the mean of its divisors is an integer number (520500066).

Almost surely, 2^1041000131 is an apocalyptic number.

1041000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1041000131 is an equidigital number, since it uses as much as digits as its factorization.

1041000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1041000131 is about 32264.5336398963. The cubic root of 1041000131 is about 1013.4840728860.

Adding to 1041000131 its reverse (1310001401), we get a palindrome (2351001532).

The spelling of 1041000131 in words is "one billion, forty-one million, one hundred thirty-one", and thus it is an aban number.