Base | Representation |
---|---|
bin | 10011011001001000… |
… | …00000010100101111 |
3 | 222212120201110201010 |
4 | 21230210000110233 |
5 | 132310243444211 |
6 | 4441034320303 |
7 | 516000460362 |
oct | 115444002457 |
9 | 28776643633 |
10 | 10411312431 |
11 | 4462a07143 |
12 | 2026889093 |
13 | c9bc8cb00 |
14 | 70aa300d9 |
15 | 40e0584a6 |
hex | 26c90052f |
10411312431 has 48 divisors (see below), whose sum is σ = 15949073664. Its totient is φ = 6017536512.
The previous prime is 10411312391. The next prime is 10411312453. The reversal of 10411312431 is 13421311401.
It is not a de Polignac number, because 10411312431 - 26 = 10411312367 is a prime.
It is a super-2 number, since 2×104113124312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10411312398 and 10411312407.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10411312631) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5575560 + ... + 5577426.
It is an arithmetic number, because the mean of its divisors is an integer number (332272368).
Almost surely, 210411312431 is an apocalyptic number.
10411312431 is a deficient number, since it is larger than the sum of its proper divisors (5537761233).
10411312431 is a wasteful number, since it uses less digits than its factorization.
10411312431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2560 (or 2547 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 10411312431 its reverse (13421311401), we get a palindrome (23832623832).
The spelling of 10411312431 in words is "ten billion, four hundred eleven million, three hundred twelve thousand, four hundred thirty-one".
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