Base | Representation |
---|---|
bin | 10011011001001000… |
… | …11011100110000011 |
3 | 222212120221010221011 |
4 | 21230210123212003 |
5 | 132310311033011 |
6 | 4441040541351 |
7 | 516001434133 |
oct | 115444334603 |
9 | 28776833834 |
10 | 10411424131 |
11 | 4462a83059 |
12 | 2026921857 |
13 | c9bccb8c4 |
14 | 70aa5cac3 |
15 | 40e07b621 |
hex | 26c91b983 |
10411424131 has 2 divisors, whose sum is σ = 10411424132. Its totient is φ = 10411424130.
The previous prime is 10411424113. The next prime is 10411424143. The reversal of 10411424131 is 13142411401.
Together with previous prime (10411424113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10411424131 - 27 = 10411424003 is a prime.
It is a super-2 number, since 2×104114241312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10411421131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5205712065 + 5205712066.
It is an arithmetic number, because the mean of its divisors is an integer number (5205712066).
Almost surely, 210411424131 is an apocalyptic number.
10411424131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10411424131 is an equidigital number, since it uses as much as digits as its factorization.
10411424131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 10411424131 its reverse (13142411401), we get a palindrome (23553835532).
The spelling of 10411424131 in words is "ten billion, four hundred eleven million, four hundred twenty-four thousand, one hundred thirty-one".
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