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10413423110953 is a prime number
BaseRepresentation
bin1001011110001001000001…
…1000101010101100101001
31100212111212100202022101201
42113202100120222230221
52331103142304022303
634051505513044201
72123226221661502
oct227422030525451
940774770668351
1010413423110953
113355342961345
1212022363b6661
135a6c9b70c265
14280025d19ba9
15130d24eb981d
hex9789062ab29

10413423110953 has 2 divisors, whose sum is σ = 10413423110954. Its totient is φ = 10413423110952.

The previous prime is 10413423110917. The next prime is 10413423110971. The reversal of 10413423110953 is 35901132431401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10396677974544 + 16745136409 = 3224388^2 + 129403^2 .

It is an emirp because it is prime and its reverse (35901132431401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10413423110953 - 229 = 10412886240041 is a prime.

It is not a weakly prime, because it can be changed into another prime (10413423110983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5206711555476 + 5206711555477.

It is an arithmetic number, because the mean of its divisors is an integer number (5206711555477).

Almost surely, 210413423110953 is an apocalyptic number.

It is an amenable number.

10413423110953 is a deficient number, since it is larger than the sum of its proper divisors (1).

10413423110953 is an equidigital number, since it uses as much as digits as its factorization.

10413423110953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 37.

The spelling of 10413423110953 in words is "ten trillion, four hundred thirteen billion, four hundred twenty-three million, one hundred ten thousand, nine hundred fifty-three".