Base | Representation |
---|---|
bin | 111110000100101… |
… | …010100001010011 |
3 | 2200120121010010121 |
4 | 332010222201103 |
5 | 4113100111011 |
6 | 251201011111 |
7 | 34543561066 |
oct | 7604524123 |
9 | 2616533117 |
10 | 1041410131 |
11 | 494937933 |
12 | 250923a97 |
13 | 1379a8818 |
14 | 9c44a8dd |
15 | 61660e71 |
hex | 3e12a853 |
1041410131 has 2 divisors, whose sum is σ = 1041410132. Its totient is φ = 1041410130.
The previous prime is 1041410113. The next prime is 1041410173. The reversal of 1041410131 is 1310141401.
Together with previous prime (1041410113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is an emirp because it is prime and its reverse (1310141401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1041410131 - 25 = 1041410099 is a prime.
It is a super-2 number, since 2×10414101312 = 2169070121898874322, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1041410231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520705065 + 520705066.
It is an arithmetic number, because the mean of its divisors is an integer number (520705066).
Almost surely, 21041410131 is an apocalyptic number.
1041410131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1041410131 is an equidigital number, since it uses as much as digits as its factorization.
1041410131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
The square root of 1041410131 is about 32270.8867402183. The cubic root of 1041410131 is about 1013.6171096703.
Adding to 1041410131 its reverse (1310141401), we get a palindrome (2351551532).
The spelling of 1041410131 in words is "one billion, forty-one million, four hundred ten thousand, one hundred thirty-one".
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