Base | Representation |
---|---|
bin | 1001011110001100110010… |
… | …0010100101010101110011 |
3 | 1100212121110200210122001122 |
4 | 2113203030202211111303 |
5 | 2331112224134442121 |
6 | 34052154004252455 |
7 | 2123263225214255 |
oct | 227431442452563 |
9 | 40777420718048 |
10 | 10414432343411 |
11 | 3355810610658 |
12 | 12024783a112b |
13 | 5a70cc82c825 |
14 | 2800bdd8bcd5 |
15 | 130d838c15ab |
hex | 978cc8a5573 |
10414432343411 has 2 divisors, whose sum is σ = 10414432343412. Its totient is φ = 10414432343410.
The previous prime is 10414432343323. The next prime is 10414432343443. The reversal of 10414432343411 is 11434323441401.
10414432343411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10414432343411 - 218 = 10414432081267 is a prime.
It is a super-2 number, since 2×104144323434112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10414432345411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5207216171705 + 5207216171706.
It is an arithmetic number, because the mean of its divisors is an integer number (5207216171706).
Almost surely, 210414432343411 is an apocalyptic number.
10414432343411 is a deficient number, since it is larger than the sum of its proper divisors (1).
10414432343411 is an equidigital number, since it uses as much as digits as its factorization.
10414432343411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 10414432343411 its reverse (11434323441401), we get a palindrome (21848755784812).
The spelling of 10414432343411 in words is "ten trillion, four hundred fourteen billion, four hundred thirty-two million, three hundred forty-three thousand, four hundred eleven".
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