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10414432343411 is a prime number
BaseRepresentation
bin1001011110001100110010…
…0010100101010101110011
31100212121110200210122001122
42113203030202211111303
52331112224134442121
634052154004252455
72123263225214255
oct227431442452563
940777420718048
1010414432343411
113355810610658
1212024783a112b
135a70cc82c825
142800bdd8bcd5
15130d838c15ab
hex978cc8a5573

10414432343411 has 2 divisors, whose sum is σ = 10414432343412. Its totient is φ = 10414432343410.

The previous prime is 10414432343323. The next prime is 10414432343443. The reversal of 10414432343411 is 11434323441401.

10414432343411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10414432343411 - 218 = 10414432081267 is a prime.

It is a super-2 number, since 2×104144323434112 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10414432345411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5207216171705 + 5207216171706.

It is an arithmetic number, because the mean of its divisors is an integer number (5207216171706).

Almost surely, 210414432343411 is an apocalyptic number.

10414432343411 is a deficient number, since it is larger than the sum of its proper divisors (1).

10414432343411 is an equidigital number, since it uses as much as digits as its factorization.

10414432343411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 10414432343411 its reverse (11434323441401), we get a palindrome (21848755784812).

The spelling of 10414432343411 in words is "ten trillion, four hundred fourteen billion, four hundred thirty-two million, three hundred forty-three thousand, four hundred eleven".