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10415133481 is a prime number
BaseRepresentation
bin10011011001100101…
…00101001100101001
3222212211220121012111
421230302211030221
5132312233232411
64441252242321
7516045113434
oct115462451451
928784817174
1010415133481
114465086a35
1220280103a1
13c9c9ca09c
1470b34681b
1540e560721
hex26cca5329

10415133481 has 2 divisors, whose sum is σ = 10415133482. Its totient is φ = 10415133480.

The previous prime is 10415133467. The next prime is 10415133497. The reversal of 10415133481 is 18433151401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8884759081 + 1530374400 = 94259^2 + 39120^2 .

It is a cyclic number.

It is not a de Polignac number, because 10415133481 - 215 = 10415100713 is a prime.

It is a super-2 number, since 2×104151334812 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10415133431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5207566740 + 5207566741.

It is an arithmetic number, because the mean of its divisors is an integer number (5207566741).

Almost surely, 210415133481 is an apocalyptic number.

It is an amenable number.

10415133481 is a deficient number, since it is larger than the sum of its proper divisors (1).

10415133481 is an equidigital number, since it uses as much as digits as its factorization.

10415133481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 10415133481 its reverse (18433151401), we get a palindrome (28848284882).

The spelling of 10415133481 in words is "ten billion, four hundred fifteen million, one hundred thirty-three thousand, four hundred eighty-one".