Base | Representation |
---|---|
bin | 110000100001011100… |
… | …1010000001011011001 |
3 | 100221221222112122221101 |
4 | 1201002321100023121 |
5 | 3201401042113313 |
6 | 115511452111401 |
7 | 10346132206315 |
oct | 1410271201331 |
9 | 327858478841 |
10 | 104201519833 |
11 | 40212050144 |
12 | 18240a65561 |
13 | 9a980cb158 |
14 | 5087070b45 |
15 | 2a9d0195dd |
hex | 1842e502d9 |
104201519833 has 2 divisors, whose sum is σ = 104201519834. Its totient is φ = 104201519832.
The previous prime is 104201519801. The next prime is 104201519893. The reversal of 104201519833 is 338915102401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 94524272704 + 9677247129 = 307448^2 + 98373^2 .
It is a cyclic number.
It is not a de Polignac number, because 104201519833 - 25 = 104201519801 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 104201519792 and 104201519801.
It is not a weakly prime, because it can be changed into another prime (104201519893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52100759916 + 52100759917.
It is an arithmetic number, because the mean of its divisors is an integer number (52100759917).
Almost surely, 2104201519833 is an apocalyptic number.
It is an amenable number.
104201519833 is a deficient number, since it is larger than the sum of its proper divisors (1).
104201519833 is an equidigital number, since it uses as much as digits as its factorization.
104201519833 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 37.
The spelling of 104201519833 in words is "one hundred four billion, two hundred one million, five hundred nineteen thousand, eight hundred thirty-three".
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