Base | Representation |
---|---|
bin | 10011011010101001… |
… | …10111001101000011 |
3 | 222220110211011120101 |
4 | 21231110313031003 |
5 | 132322033321011 |
6 | 4442213023231 |
7 | 516214362535 |
oct | 115524671503 |
9 | 28813734511 |
10 | 10424120131 |
11 | 446a164817 |
12 | 202b024b17 |
13 | ca1825629 |
14 | 70c605855 |
15 | 4102382c1 |
hex | 26d537343 |
10424120131 has 2 divisors, whose sum is σ = 10424120132. Its totient is φ = 10424120130.
The previous prime is 10424120117. The next prime is 10424120183. The reversal of 10424120131 is 13102142401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10424120131 - 229 = 9887249219 is a prime.
It is a super-2 number, since 2×104241201312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10424120099 and 10424120108.
It is not a weakly prime, because it can be changed into another prime (10424120101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5212060065 + 5212060066.
It is an arithmetic number, because the mean of its divisors is an integer number (5212060066).
Almost surely, 210424120131 is an apocalyptic number.
10424120131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10424120131 is an equidigital number, since it uses as much as digits as its factorization.
10424120131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 10424120131 its reverse (13102142401), we get a palindrome (23526262532).
The spelling of 10424120131 in words is "ten billion, four hundred twenty-four million, one hundred twenty thousand, one hundred thirty-one".
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