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104330110019 is a prime number
BaseRepresentation
bin110000100101010001…
…1110010010001000011
3100222021221111201111212
41201022203302101003
53202132002010034
6115532324200335
710352253205652
oct1411243622103
9328257451455
10104330110019
1140278699923
1218277b390ab
139ab8942015
14509a185199
152aa946a2ce
hex184a8f2443

104330110019 has 2 divisors, whose sum is σ = 104330110020. Its totient is φ = 104330110018.

The previous prime is 104330109979. The next prime is 104330110039. The reversal of 104330110019 is 910011033401.

It is a strong prime.

It is an emirp because it is prime and its reverse (910011033401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 104330110019 - 232 = 100035142723 is a prime.

It is a super-2 number, since 2×1043301100192 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 104330109976 and 104330110003.

It is not a weakly prime, because it can be changed into another prime (104330110039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52165055009 + 52165055010.

It is an arithmetic number, because the mean of its divisors is an integer number (52165055010).

Almost surely, 2104330110019 is an apocalyptic number.

104330110019 is a deficient number, since it is larger than the sum of its proper divisors (1).

104330110019 is an equidigital number, since it uses as much as digits as its factorization.

104330110019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 23.

The spelling of 104330110019 in words is "one hundred four billion, three hundred thirty million, one hundred ten thousand, nineteen".