Base | Representation |
---|---|
bin | 110000100101010111… |
… | …0110110100001101011 |
3 | 100222022010222002222111 |
4 | 1201022232312201223 |
5 | 3202133222323201 |
6 | 115532510303151 |
7 | 10352316650533 |
oct | 1411256664153 |
9 | 328263862874 |
10 | 104333011051 |
11 | 4027a2a0475 |
12 | 18278ab7ab7 |
13 | 9ab94195c9 |
14 | 509a6dc4c3 |
15 | 2aa983eb51 |
hex | 184abb686b |
104333011051 has 2 divisors, whose sum is σ = 104333011052. Its totient is φ = 104333011050.
The previous prime is 104333011039. The next prime is 104333011157. The reversal of 104333011051 is 150110333401.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 104333011051 - 25 = 104333011019 is a prime.
It is not a weakly prime, because it can be changed into another prime (104333081051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52166505525 + 52166505526.
It is an arithmetic number, because the mean of its divisors is an integer number (52166505526).
Almost surely, 2104333011051 is an apocalyptic number.
104333011051 is a deficient number, since it is larger than the sum of its proper divisors (1).
104333011051 is an equidigital number, since it uses as much as digits as its factorization.
104333011051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 104333011051 its reverse (150110333401), we get a palindrome (254443344452).
The spelling of 104333011051 in words is "one hundred four billion, three hundred thirty-three million, eleven thousand, fifty-one".
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