Base | Representation |
---|---|
bin | 10011011100101101… |
… | …11011101110000101 |
3 | 222221200102010010221 |
4 | 21232112323232011 |
5 | 132341002041013 |
6 | 4444032144341 |
7 | 516514530265 |
oct | 115626735605 |
9 | 28850363127 |
10 | 10441440133 |
11 | 4478a14573 |
12 | 20349980b1 |
13 | ca52aac57 |
14 | 710a337a5 |
15 | 411a0a08d |
hex | 26e5bbb85 |
10441440133 has 4 divisors (see below), whose sum is σ = 10441716640. Its totient is φ = 10441163628.
The previous prime is 10441440131. The next prime is 10441440151. The reversal of 10441440133 is 33104414401.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10441440133 - 21 = 10441440131 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10441440098 and 10441440107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10441440131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70563 + ... + 160816.
It is an arithmetic number, because the mean of its divisors is an integer number (2610429160).
Almost surely, 210441440133 is an apocalyptic number.
It is an amenable number.
10441440133 is a deficient number, since it is larger than the sum of its proper divisors (276507).
10441440133 is an equidigital number, since it uses as much as digits as its factorization.
10441440133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 276506.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 10441440133 its reverse (33104414401), we get a palindrome (43545854534).
The spelling of 10441440133 in words is "ten billion, four hundred forty-one million, four hundred forty thousand, one hundred thirty-three".
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