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104521133011481 is a prime number
BaseRepresentation
bin10111110000111110111001…
…000000010011001000011001
3111201002010022110201011021022
4113300332321000103020121
5102144433240022331411
61010144202353452225
731005255053515304
oct2760767100231031
9451063273634238
10104521133011481
11303381887a758a
12b880a8bb71075
1346423ba405664
141bb4bc7d0db3b
15c13c7b830edb
hex5f0fb9013219

104521133011481 has 2 divisors, whose sum is σ = 104521133011482. Its totient is φ = 104521133011480.

The previous prime is 104521133011453. The next prime is 104521133011499. The reversal of 104521133011481 is 184110331125401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62196740293081 + 42324392718400 = 7886491^2 + 6505720^2 .

It is a cyclic number.

It is not a de Polignac number, because 104521133011481 - 242 = 100123086500377 is a prime.

It is a super-2 number, since 2×1045211330114812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (104521133011781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52260566505740 + 52260566505741.

It is an arithmetic number, because the mean of its divisors is an integer number (52260566505741).

Almost surely, 2104521133011481 is an apocalyptic number.

It is an amenable number.

104521133011481 is a deficient number, since it is larger than the sum of its proper divisors (1).

104521133011481 is an equidigital number, since it uses as much as digits as its factorization.

104521133011481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 35.

Adding to 104521133011481 its reverse (184110331125401), we get a palindrome (288631464136882).

The spelling of 104521133011481 in words is "one hundred four trillion, five hundred twenty-one billion, one hundred thirty-three million, eleven thousand, four hundred eighty-one".