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10491252809 is a prime number
BaseRepresentation
bin10011100010101001…
…11101000001001001
31000002011010212021212
421301110331001021
5132441230042214
64453011542505
7520661114612
oct116124750111
930064125255
1010491252809
1144a4047574
1220495baa35
13cb26cbccb
147174bcc09
1541609953e
hex27153d049

10491252809 has 2 divisors, whose sum is σ = 10491252810. Its totient is φ = 10491252808.

The previous prime is 10491252797. The next prime is 10491252833. The reversal of 10491252809 is 90825219401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10208071225 + 283181584 = 101035^2 + 16828^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10491252809 is a prime.

It is a super-3 number, since 3×104912528093 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (10491252869) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5245626404 + 5245626405.

It is an arithmetic number, because the mean of its divisors is an integer number (5245626405).

Almost surely, 210491252809 is an apocalyptic number.

It is an amenable number.

10491252809 is a deficient number, since it is larger than the sum of its proper divisors (1).

10491252809 is an equidigital number, since it uses as much as digits as its factorization.

10491252809 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 41.

The spelling of 10491252809 in words is "ten billion, four hundred ninety-one million, two hundred fifty-two thousand, eight hundred nine".