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104941307 is a prime number
BaseRepresentation
bin1100100000101…
…00011011111011
321022110120102002
412100110123323
5203331110212
614225131215
72412662222
oct620243373
9238416362
10104941307
1154266a59
122b189b0b
1318983963
14dd19cb9
15932dac2
hex64146fb

104941307 has 2 divisors, whose sum is σ = 104941308. Its totient is φ = 104941306.

The previous prime is 104941301. The next prime is 104941327. The reversal of 104941307 is 703149401.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 104941307 - 212 = 104937211 is a prime.

It is a super-2 number, since 2×1049413072 = 22025355829736498, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 104941307.

It is not a weakly prime, because it can be changed into another prime (104941301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52470653 + 52470654.

It is an arithmetic number, because the mean of its divisors is an integer number (52470654).

Almost surely, 2104941307 is an apocalyptic number.

104941307 is a deficient number, since it is larger than the sum of its proper divisors (1).

104941307 is an equidigital number, since it uses as much as digits as its factorization.

104941307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024, while the sum is 29.

The square root of 104941307 is about 10244.0864404787. The cubic root of 104941307 is about 471.6814782787.

The spelling of 104941307 in words is "one hundred four million, nine hundred forty-one thousand, three hundred seven".