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105011532012 = 2238750961001
BaseRepresentation
bin110000111001100101…
…1001101000011101100
3101001001102201112202110
41201303023031003230
53210030423011022
6120124105324020
710405166203002
oct1416313150354
9331042645673
10105011532012
11405982aa2a2
1218428196610
139b96b782ba
145122884a72
152ae91bd00c
hex18732cd0ec

105011532012 has 12 divisors (see below), whose sum is σ = 245026908056. Its totient is φ = 35003844000.

The previous prime is 105011532007. The next prime is 105011532047. The reversal of 105011532012 is 210235110501.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×1050115320122 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 105011532012.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4375480489 + ... + 4375480512.

Almost surely, 2105011532012 is an apocalyptic number.

105011532012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

105011532012 is an abundant number, since it is smaller than the sum of its proper divisors (140015376044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

105011532012 is a wasteful number, since it uses less digits than its factorization.

105011532012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8750961008 (or 8750961006 counting only the distinct ones).

The product of its (nonzero) digits is 300, while the sum is 21.

Adding to 105011532012 its reverse (210235110501), we get a palindrome (315246642513).

The spelling of 105011532012 in words is "one hundred five billion, eleven million, five hundred thirty-two thousand, twelve".

Divisors: 1 2 3 4 6 12 8750961001 17501922002 26252883003 35003844004 52505766006 105011532012