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1050116113 is a prime number
BaseRepresentation
bin111110100101111…
…000000000010001
32201011222102111101
4332211320000101
54122312203423
6252111344401
735010561004
oct7645700021
92634872441
101050116113
11499843862
12253822101
131397363a7
149d67553b
15622d07ad
hex3e978011

1050116113 has 2 divisors, whose sum is σ = 1050116114. Its totient is φ = 1050116112.

The previous prime is 1050116101. The next prime is 1050116147. The reversal of 1050116113 is 3116110501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1047946384 + 2169729 = 32372^2 + 1473^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1050116113 is a prime.

It is a super-2 number, since 2×10501161132 = 2205487701564457538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1050116153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525058056 + 525058057.

It is an arithmetic number, because the mean of its divisors is an integer number (525058057).

Almost surely, 21050116113 is an apocalyptic number.

It is an amenable number.

1050116113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1050116113 is an equidigital number, since it uses as much as digits as its factorization.

1050116113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 19.

The square root of 1050116113 is about 32405.4951049972. The cubic root of 1050116113 is about 1016.4338210943.

Adding to 1050116113 its reverse (3116110501), we get a palindrome (4166226614).

The spelling of 1050116113 in words is "one billion, fifty million, one hundred sixteen thousand, one hundred thirteen".