Search a number
-
+
105013091 is a prime number
BaseRepresentation
bin1100100001001…
…01111101100011
321022121012212202
412100211331203
5203340404331
614230443415
72413411421
oct620457543
9238535782
10105013091
1154305987
122b20356b
13189aa531
14dd38111
159344ecb
hex6425f63

105013091 has 2 divisors, whose sum is σ = 105013092. Its totient is φ = 105013090.

The previous prime is 105013079. The next prime is 105013109. The reversal of 105013091 is 190310501.

Together with next prime (105013109) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 105013091 - 214 = 104996707 is a prime.

It is a super-2 number, since 2×1050130912 = 22055498562748562, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (105013291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52506545 + 52506546.

It is an arithmetic number, because the mean of its divisors is an integer number (52506546).

Almost surely, 2105013091 is an apocalyptic number.

105013091 is a deficient number, since it is larger than the sum of its proper divisors (1).

105013091 is an equidigital number, since it uses as much as digits as its factorization.

105013091 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 20.

The square root of 105013091 is about 10247.5895214436. The cubic root of 105013091 is about 471.7890033540.

Adding to 105013091 its reverse (190310501), we get a palindrome (295323592).

It can be divided in two parts, 1050 and 13091, that added together give a palindrome (14141).

The spelling of 105013091 in words is "one hundred five million, thirteen thousand, ninety-one".