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105015000401 is a prime number
BaseRepresentation
bin110000111001101100…
…0011011110101010001
3101001001200020202111022
41201303120123311101
53210032320003101
6120124311525225
710405240526633
oct1416330336521
9331050222438
10105015000401
114059a259133
1218429389815
139b977c0bbc
145123108a53
152ae9655a1b
hex187361bd51

105015000401 has 2 divisors, whose sum is σ = 105015000402. Its totient is φ = 105015000400.

The previous prime is 105015000397. The next prime is 105015000443. The reversal of 105015000401 is 104000510501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91808394001 + 13206606400 = 302999^2 + 114920^2 .

It is a cyclic number.

It is not a de Polignac number, because 105015000401 - 22 = 105015000397 is a prime.

It is a super-2 number, since 2×1050150004012 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 105015000401.

It is not a weakly prime, because it can be changed into another prime (105015000451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52507500200 + 52507500201.

It is an arithmetic number, because the mean of its divisors is an integer number (52507500201).

Almost surely, 2105015000401 is an apocalyptic number.

It is an amenable number.

105015000401 is a deficient number, since it is larger than the sum of its proper divisors (1).

105015000401 is an equidigital number, since it uses as much as digits as its factorization.

105015000401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100, while the sum is 17.

Adding to 105015000401 its reverse (104000510501), we get a palindrome (209015510902).

The spelling of 105015000401 in words is "one hundred five billion, fifteen million, four hundred one", and thus it is an aban number.