Base | Representation |
---|---|
bin | 10011100011111001… |
… | …00100111111000101 |
3 | 1000002212200121000120 |
4 | 21301330210333011 |
5 | 133001404441013 |
6 | 4454022332153 |
7 | 521145316425 |
oct | 116174447705 |
9 | 30085617016 |
10 | 10501640133 |
11 | 44a99a1736 |
12 | 2050b8a059 |
13 | cb48c7c5a |
14 | 718a24485 |
15 | 416e4c123 |
hex | 271f24fc5 |
10501640133 has 4 divisors (see below), whose sum is σ = 14002186848. Its totient is φ = 7001093420.
The previous prime is 10501640117. The next prime is 10501640137. The reversal of 10501640133 is 33104610501.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10501640133 - 24 = 10501640117 is a prime.
It is a super-2 number, since 2×105016401332 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10501640137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1750273353 + ... + 1750273358.
It is an arithmetic number, because the mean of its divisors is an integer number (3500546712).
Almost surely, 210501640133 is an apocalyptic number.
It is an amenable number.
10501640133 is a deficient number, since it is larger than the sum of its proper divisors (3500546715).
10501640133 is an equidigital number, since it uses as much as digits as its factorization.
10501640133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3500546714.
The product of its (nonzero) digits is 1080, while the sum is 24.
The spelling of 10501640133 in words is "ten billion, five hundred one million, six hundred forty thousand, one hundred thirty-three".
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