1050345133 has 4 divisors (see below), whose sum is σ = 1074771808. Its totient is φ = 1025918460.

The previous prime is 1050345091. The next prime is 1050345139. The reversal of 1050345133 is 3315430501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3315430501 = 31 ⋅106949371.

It is a cyclic number.

It is not a de Polignac number, because 1050345133 - 2⁹ = 1050344621 is a prime.

It is a super-2 number, since 2×1050345133² = 2206449796833575378, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1050345098 and 1050345107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1050345139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12213273 + ... + 12213358.

It is an arithmetic number, because the mean of its divisors is an integer number (268692952).

Almost surely, 2^1050345133 is an apocalyptic number.

It is an amenable number.

1050345133 is a deficient number, since it is larger than the sum of its proper divisors (24426675).

1050345133 is an equidigital number, since it uses as much as digits as its factorization.

1050345133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24426674.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 1050345133 is about 32409.0285722976. The cubic root of 1050345133 is about 1016.5077071310.

Adding to 1050345133 its reverse (3315430501), we get a palindrome (4365775634).

The spelling of 1050345133 in words is "one billion, fifty million, three hundred forty-five thousand, one hundred thirty-three".