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1050381433 is a prime number
BaseRepresentation
bin111110100110111…
…000110001111001
32201012110220110001
4332212320301321
54122344201213
6252121153001
735013044353
oct7646706171
92635426401
101050381433
11499a05132
1225392b761
131397ca09a
149d7040d3
15623341dd
hex3e9b8c79

1050381433 has 2 divisors, whose sum is σ = 1050381434. Its totient is φ = 1050381432.

The previous prime is 1050381407. The next prime is 1050381469. The reversal of 1050381433 is 3341830501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1010476944 + 39904489 = 31788^2 + 6317^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1050381433 is a prime.

It is a super-2 number, since 2×10503814332 = 2206602309582266978, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1050381833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525190716 + 525190717.

It is an arithmetic number, because the mean of its divisors is an integer number (525190717).

Almost surely, 21050381433 is an apocalyptic number.

It is an amenable number.

1050381433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1050381433 is an equidigital number, since it uses as much as digits as its factorization.

1050381433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 28.

The square root of 1050381433 is about 32409.5885965867. The cubic root of 1050381433 is about 1016.5194171882.

The spelling of 1050381433 in words is "one billion, fifty million, three hundred eighty-one thousand, four hundred thirty-three".