105040333542013 has 4 divisors (see below), whose sum is σ = 105049731453660. Its totient is φ = 105030935630368.

The previous prime is 105040333541989. The next prime is 105040333542031. The reversal of 105040333542013 is 310245333040501.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 90687586138009 + 14352747404004 = 9523003^2 + 3788502^2 .

It is a cyclic number.

It is not a de Polignac number, because 105040333542013 - 2²¹ = 105040331444861 is a prime.

It is a super-2 number, since 2×105040333542013² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 105040333542013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (105040333042013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4698939058 + ... + 4698961411.

It is an arithmetic number, because the mean of its divisors is an integer number (26262432863415).

Almost surely, 2^{105040333542013} is an apocalyptic number.

It is an amenable number.

105040333542013 is a deficient number, since it is larger than the sum of its proper divisors (9397911647).

105040333542013 is an equidigital number, since it uses as much as digits as its factorization.

105040333542013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9397911646.

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 105040333542013 its reverse (310245333040501), we get a palindrome (415285666582514).

The spelling of 105040333542013 in words is "one hundred five trillion, forty billion, three hundred thirty-three million, five hundred forty-two thousand, thirteen".