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105041408461313 is a prime number
BaseRepresentation
bin10111111000100011011011…
…110101101000101000000001
3111202220212020100202102220012
4113320203123311220220001
5102231444301031230223
61011223205030154305
731060664011051412
oct2770433365505001
9452825210672805
10105041408461313
11305188a171a595
12b94588b1b2995
13467c49301160c
141bd2061c3b809
15c2257c48ec78
hex5f88dbd68a01

105041408461313 has 2 divisors, whose sum is σ = 105041408461314. Its totient is φ = 105041408461312.

The previous prime is 105041408461291. The next prime is 105041408461349. The reversal of 105041408461313 is 313164804140501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96078282614209 + 8963125847104 = 9801953^2 + 2993848^2 .

It is a cyclic number.

It is not a de Polignac number, because 105041408461313 - 236 = 104972688984577 is a prime.

It is a super-2 number, since 2×1050414084613132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (105041408461013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52520704230656 + 52520704230657.

It is an arithmetic number, because the mean of its divisors is an integer number (52520704230657).

Almost surely, 2105041408461313 is an apocalyptic number.

It is an amenable number.

105041408461313 is a deficient number, since it is larger than the sum of its proper divisors (1).

105041408461313 is an equidigital number, since it uses as much as digits as its factorization.

105041408461313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 138240, while the sum is 41.

The spelling of 105041408461313 in words is "one hundred five trillion, forty-one billion, four hundred eight million, four hundred sixty-one thousand, three hundred thirteen".