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1050552513245 = 5210110502649
BaseRepresentation
bin11110100100110011100…
…11110011001011011101
310201102122210220011210102
433102121303303023131
5114203012420410440
62122341150150445
7135620446011404
oct17223163631335
93642583804712
101050552513245
1137559a562364
1214b72bab2425
13780b3648981
1438bc02bc63b
151c4d9898b15
hexf499cf32dd

1050552513245 has 4 divisors (see below), whose sum is σ = 1260663015900. Its totient is φ = 840442010592.

The previous prime is 1050552513239. The next prime is 1050552513293. The reversal of 1050552513245 is 5423152550501.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 777142744249 + 273409768996 = 881557^2 + 522886^2 .

It is a cyclic number.

It is not a de Polignac number, because 1050552513245 - 26 = 1050552513181 is a prime.

It is a super-2 number, since 2×10505525132452 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1050552513199 and 1050552513208.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105055251320 + ... + 105055251329.

It is an arithmetic number, because the mean of its divisors is an integer number (315165753975).

Almost surely, 21050552513245 is an apocalyptic number.

It is an amenable number.

1050552513245 is a deficient number, since it is larger than the sum of its proper divisors (210110502655).

1050552513245 is an equidigital number, since it uses as much as digits as its factorization.

1050552513245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 210110502654.

The product of its (nonzero) digits is 150000, while the sum is 38.

The spelling of 1050552513245 in words is "one trillion, fifty billion, five hundred fifty-two million, five hundred thirteen thousand, two hundred forty-five".

Divisors: 1 5 210110502649 1050552513245