1051005113 has 2 divisors, whose sum is σ = 1051005114. Its totient is φ = 1051005112.

The previous prime is 1051005103. The next prime is 1051005133. The reversal of 1051005113 is 3115001501.

1051005113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 692584489 + 358420624 = 26317^2 + 18932^2 .

It is an emirp because it is prime and its reverse (3115001501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1051005113 - 2⁶ = 1051005049 is a prime.

It is a super-2 number, since 2×1051005113² = 2209223495104285538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1051005091 and 1051005100.

It is not a weakly prime, because it can be changed into another prime (1051005103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525502556 + 525502557.

It is an arithmetic number, because the mean of its divisors is an integer number (525502557).

Almost surely, 2^1051005113 is an apocalyptic number.

It is an amenable number.

1051005113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1051005113 is an equidigital number, since it uses as much as digits as its factorization.

1051005113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75, while the sum is 17.

The square root of 1051005113 is about 32419.2090125592. The cubic root of 1051005113 is about 1016.7205686850.

Adding to 1051005113 its reverse (3115001501), we get a palindrome (4166006614).

The spelling of 1051005113 in words is "one billion, fifty-one million, five thousand, one hundred thirteen".