Base | Representation |
---|---|
bin | 10111111001100110001111… |
… | …101000101110110010110011 |
3 | 111210011201101202200110111012 |
4 | 113321212033220232302303 |
5 | 102234133204440014243 |
6 | 1011320151213341135 |
7 | 31066113464662235 |
oct | 2771461750566263 |
9 | 453151352613435 |
10 | 105113144454323 |
11 | 30546263828925 |
12 | b95776b4977ab |
13 | 4686185cc8265 |
14 | 1bd5709228255 |
15 | c2437a1b3d18 |
hex | 5f998fa2ecb3 |
105113144454323 has 2 divisors, whose sum is σ = 105113144454324. Its totient is φ = 105113144454322.
The previous prime is 105113144454293. The next prime is 105113144454347. The reversal of 105113144454323 is 323454441311501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 105113144454323 - 238 = 104838266547379 is a prime.
It is a super-2 number, since 2×1051131444543232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (105113144451323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52556572227161 + 52556572227162.
It is an arithmetic number, because the mean of its divisors is an integer number (52556572227162).
Almost surely, 2105113144454323 is an apocalyptic number.
105113144454323 is a deficient number, since it is larger than the sum of its proper divisors (1).
105113144454323 is an equidigital number, since it uses as much as digits as its factorization.
105113144454323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 105113144454323 its reverse (323454441311501), we get a palindrome (428567585765824).
The spelling of 105113144454323 in words is "one hundred five trillion, one hundred thirteen billion, one hundred forty-four million, four hundred fifty-four thousand, three hundred twenty-three".
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