Base | Representation |
---|---|
bin | 11110100101111010111… |
… | …11101001111001100010 |
3 | 10201111012112110020021012 |
4 | 33102331133221321202 |
5 | 114210224202242010 |
6 | 2122520414300522 |
7 | 135641335611245 |
oct | 17227537517142 |
9 | 3644175406235 |
10 | 1051151212130 |
11 | 375877501728 |
12 | 14b8784b7742 |
13 | 7817a6aa276 |
14 | 38c39a0725c |
15 | 1c52220b005 |
hex | f4bd7e9e62 |
1051151212130 has 8 divisors (see below), whose sum is σ = 1892072181852. Its totient is φ = 420460484848.
The previous prime is 1051151212121. The next prime is 1051151212159. The reversal of 1051151212130 is 312121511501.
It can be written as a sum of positive squares in 2 ways, for example, as 1049573613169 + 1577598961 = 1024487^2 + 39719^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×10511512121302 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1051151212096 and 1051151212105.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52557560597 + ... + 52557560616.
Almost surely, 21051151212130 is an apocalyptic number.
1051151212130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1051151212130 is a deficient number, since it is larger than the sum of its proper divisors (840920969722).
1051151212130 is a wasteful number, since it uses less digits than its factorization.
1051151212130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 105115121220.
The product of its (nonzero) digits is 300, while the sum is 23.
Adding to 1051151212130 its reverse (312121511501), we get a palindrome (1363272723631).
The spelling of 1051151212130 in words is "one trillion, fifty-one billion, one hundred fifty-one million, two hundred twelve thousand, one hundred thirty".
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