1051433147 has 2 divisors, whose sum is σ = 1051433148. Its totient is φ = 1051433146.

The previous prime is 1051433143. The next prime is 1051433171. The reversal of 1051433147 is 7413341501.

It is a weak prime.

It is an emirp because it is prime and its reverse (7413341501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1051433147 - 2² = 1051433143 is a prime.

It is a super-2 number, since 2×1051433147² = 2211023325220647218, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1051433143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 525716573 + 525716574.

It is an arithmetic number, because the mean of its divisors is an integer number (525716574).

Almost surely, 2^1051433147 is an apocalyptic number.

1051433147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1051433147 is an equidigital number, since it uses as much as digits as its factorization.

1051433147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 29.

The square root of 1051433147 is about 32425.8098896543. The cubic root of 1051433147 is about 1016.8585736928.

Adding to 1051433147 its reverse (7413341501), we get a palindrome (8464774648).

The spelling of 1051433147 in words is "one billion, fifty-one million, four hundred thirty-three thousand, one hundred forty-seven".