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10515310133 = 13180269543
BaseRepresentation
bin10011100101100001…
…01110011000110101
31000010211102002201212
421302300232120311
5133013404411013
64455231331205
7521402442566
oct116260563065
930124362655
1010515310133
114506689159
122055680b05
13cb76a3103
1471a78216d
1541824c6a8
hex272c2e635

10515310133 has 4 divisors (see below), whose sum is σ = 10595579808. Its totient is φ = 10435040460.

The previous prime is 10515310097. The next prime is 10515310181. The reversal of 10515310133 is 33101351501.

10515310133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10515310133 - 210 = 10515309109 is a prime.

It is a super-2 number, since 2×105153101332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10515310099 and 10515310108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10515210133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40134641 + ... + 40134902.

It is an arithmetic number, because the mean of its divisors is an integer number (2648894952).

Almost surely, 210515310133 is an apocalyptic number.

It is an amenable number.

10515310133 is a deficient number, since it is larger than the sum of its proper divisors (80269675).

10515310133 is an equidigital number, since it uses as much as digits as its factorization.

10515310133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80269674.

The product of its (nonzero) digits is 675, while the sum is 23.

Adding to 10515310133 its reverse (33101351501), we get a palindrome (43616661634).

The spelling of 10515310133 in words is "ten billion, five hundred fifteen million, three hundred ten thousand, one hundred thirty-three".

Divisors: 1 131 80269543 10515310133