Base | Representation |
---|---|
bin | 11110100111100101011… |
… | …01111101010100010011 |
3 | 10201120111202200101102011 |
4 | 33103302231331110103 |
5 | 114214041300413011 |
6 | 2123145153203351 |
7 | 136002430522555 |
oct | 17236255752423 |
9 | 3646452611364 |
10 | 1052044154131 |
11 | 376195553223 |
12 | 14ba87560557 |
13 | 782906a2209 |
14 | 38cc24474d5 |
15 | 1c5757e1621 |
hex | f4f2b7d513 |
1052044154131 has 32 divisors (see below), whose sum is σ = 1142258319360. Its totient is φ = 965156544000.
The previous prime is 1052044154123. The next prime is 1052044154143. The reversal of 1052044154131 is 1314514402501.
It is a cyclic number.
It is not a de Polignac number, because 1052044154131 - 23 = 1052044154123 is a prime.
It is a super-2 number, since 2×10520441541312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1052044154093 and 1052044154102.
It is not an unprimeable number, because it can be changed into a prime (1052044154101) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 284257581 + ... + 284261281.
It is an arithmetic number, because the mean of its divisors is an integer number (35695572480).
Almost surely, 21052044154131 is an apocalyptic number.
1052044154131 is a deficient number, since it is larger than the sum of its proper divisors (90214165229).
1052044154131 is a wasteful number, since it uses less digits than its factorization.
1052044154131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5115.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 1052044154131 its reverse (1314514402501), we get a palindrome (2366558556632).
The spelling of 1052044154131 in words is "one trillion, fifty-two billion, forty-four million, one hundred fifty-four thousand, one hundred thirty-one".
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