Base | Representation |
---|---|
bin | 11110100111101110110… |
… | …00000111000101111011 |
3 | 10201120201012202021100011 |
4 | 33103313120013011323 |
5 | 114214221303004313 |
6 | 2123201024322351 |
7 | 136004400050332 |
oct | 17236730070573 |
9 | 3646635667304 |
10 | 1052122313083 |
11 | 3762256871a6 |
12 | 14baa97733b7 |
13 | 782a393960a |
14 | 38ccc990d19 |
15 | 1c57c5ce93d |
hex | f4f760717b |
1052122313083 has 2 divisors, whose sum is σ = 1052122313084. Its totient is φ = 1052122313082.
The previous prime is 1052122313051. The next prime is 1052122313087. The reversal of 1052122313083 is 3803132212501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1052122313083 - 25 = 1052122313051 is a prime.
It is a super-2 number, since 2×10521223130832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1052122313087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526061156541 + 526061156542.
It is an arithmetic number, because the mean of its divisors is an integer number (526061156542).
Almost surely, 21052122313083 is an apocalyptic number.
1052122313083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1052122313083 is an equidigital number, since it uses as much as digits as its factorization.
1052122313083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 1052122313083 its reverse (3803132212501), we get a palindrome (4855254525584).
The spelling of 1052122313083 in words is "one trillion, fifty-two billion, one hundred twenty-two million, three hundred thirteen thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •