Base | Representation |
---|---|
bin | 11110100111110010010… |
… | …01111001111011000011 |
3 | 10201120210021212211001110 |
4 | 33103321021321323003 |
5 | 114214301422043210 |
6 | 2123204011534403 |
7 | 136005211441542 |
oct | 17237111717303 |
9 | 3646707784043 |
10 | 1052152143555 |
11 | 376240501287 |
12 | 14bab775a403 |
13 | 782a9b82396 |
14 | 38cd2918159 |
15 | 1c580023420 |
hex | f4f9279ec3 |
1052152143555 has 32 divisors (see below), whose sum is σ = 1700959917888. Its totient is φ = 555310080000.
The previous prime is 1052152143547. The next prime is 1052152143557. The reversal of 1052152143555 is 5553412512501.
It is not a de Polignac number, because 1052152143555 - 23 = 1052152143547 is a prime.
It is a super-2 number, since 2×10521521435552 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1052152143557) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18888645 + ... + 18944265.
It is an arithmetic number, because the mean of its divisors is an integer number (53154997434).
Almost surely, 21052152143555 is an apocalyptic number.
1052152143555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1052152143555 is a deficient number, since it is larger than the sum of its proper divisors (648807774333).
1052152143555 is a wasteful number, since it uses less digits than its factorization.
1052152143555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68727.
The product of its (nonzero) digits is 150000, while the sum is 39.
The spelling of 1052152143555 in words is "one trillion, fifty-two billion, one hundred fifty-two million, one hundred forty-three thousand, five hundred fifty-five".
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