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10521534439993 is a prime number
BaseRepresentation
bin1001100100011011110001…
…0100101010001000111001
31101020211220211021212021111
42121012330110222020321
52334341100304034433
634213305354040321
72134104301055563
oct231067424521071
941224824255244
1010521534439993
113397180993a65
12121b1887190a1
135b423a841085
14285360344333
15133a51390dcd
hex991bc52a239

10521534439993 has 2 divisors, whose sum is σ = 10521534439994. Its totient is φ = 10521534439992.

The previous prime is 10521534439957. The next prime is 10521534440071. The reversal of 10521534439993 is 39993443512501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10176304161024 + 345230278969 = 3190032^2 + 587563^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10521534439993 is a prime.

It is a super-2 number, since 2×105215344399932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10521534430993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5260767219996 + 5260767219997.

It is an arithmetic number, because the mean of its divisors is an integer number (5260767219997).

Almost surely, 210521534439993 is an apocalyptic number.

It is an amenable number.

10521534439993 is a deficient number, since it is larger than the sum of its proper divisors (1).

10521534439993 is an equidigital number, since it uses as much as digits as its factorization.

10521534439993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15746400, while the sum is 58.

The spelling of 10521534439993 in words is "ten trillion, five hundred twenty-one billion, five hundred thirty-four million, four hundred thirty-nine thousand, nine hundred ninety-three".