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10523488433 is a prime number
BaseRepresentation
bin10011100110011111…
…11011000010110001
31000011101210121020212
421303033323002301
5133023003112213
64500122513505
7521532114203
oct116317730261
930141717225
1010523488433
114510264687
122058365895
13cb92a7743
1471b8b0773
15418d159a8
hex2733fb0b1

10523488433 has 2 divisors, whose sum is σ = 10523488434. Its totient is φ = 10523488432.

The previous prime is 10523488403. The next prime is 10523488453. The reversal of 10523488433 is 33488432501.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10127000689 + 396487744 = 100633^2 + 19912^2 .

It is a cyclic number.

It is not a de Polignac number, because 10523488433 - 26 = 10523488369 is a prime.

It is a super-2 number, since 2×105234884332 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10523488403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5261744216 + 5261744217.

It is an arithmetic number, because the mean of its divisors is an integer number (5261744217).

Almost surely, 210523488433 is an apocalyptic number.

It is an amenable number.

10523488433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10523488433 is an equidigital number, since it uses as much as digits as its factorization.

10523488433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 276480, while the sum is 41.

The spelling of 10523488433 in words is "ten billion, five hundred twenty-three million, four hundred eighty-eight thousand, four hundred thirty-three".