Base | Representation |
---|---|
bin | 110001000000010000… |
… | …0001011000000011001 |
3 | 101001122000110121212211 |
4 | 1202000200023000121 |
5 | 3211010143214231 |
6 | 120202214035121 |
7 | 10413552603205 |
oct | 1420040130031 |
9 | 331560417784 |
10 | 105235132441 |
11 | 406a254163a |
12 | 1848b048aa1 |
13 | 9c012a674a |
14 | 514444bb05 |
15 | 2b0db39eb1 |
hex | 188080b019 |
105235132441 has 2 divisors, whose sum is σ = 105235132442. Its totient is φ = 105235132440.
The previous prime is 105235132433. The next prime is 105235132447. The reversal of 105235132441 is 144231532501.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74966440000 + 30268692441 = 273800^2 + 173979^2 .
It is a cyclic number.
It is not a de Polignac number, because 105235132441 - 23 = 105235132433 is a prime.
It is a super-2 number, since 2×1052351324412 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (105235132447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52617566220 + 52617566221.
It is an arithmetic number, because the mean of its divisors is an integer number (52617566221).
Almost surely, 2105235132441 is an apocalyptic number.
It is an amenable number.
105235132441 is a deficient number, since it is larger than the sum of its proper divisors (1).
105235132441 is an equidigital number, since it uses as much as digits as its factorization.
105235132441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 105235132441 its reverse (144231532501), we get a palindrome (249466664942).
The spelling of 105235132441 in words is "one hundred five billion, two hundred thirty-five million, one hundred thirty-two thousand, four hundred forty-one".
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