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1052442134243 is a prime number
BaseRepresentation
bin11110101000010100111…
…00001000011011100011
310201121112111112212111022
433110022130020123203
5114220400141243433
62123252451240055
7136015332352463
oct17241234103343
93647474485438
101052442134243
1137637a169605
1214bb788a902b
1378324c872c6
1438d1d243ba3
151c59a706698
hexf50a7086e3

1052442134243 has 2 divisors, whose sum is σ = 1052442134244. Its totient is φ = 1052442134242.

The previous prime is 1052442134189. The next prime is 1052442134257. The reversal of 1052442134243 is 3424312442501.

It is a strong prime.

It is an emirp because it is prime and its reverse (3424312442501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1052442134243 - 28 = 1052442133987 is a prime.

It is a super-2 number, since 2×10524421342432 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1052442134743) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526221067121 + 526221067122.

It is an arithmetic number, because the mean of its divisors is an integer number (526221067122).

Almost surely, 21052442134243 is an apocalyptic number.

1052442134243 is a deficient number, since it is larger than the sum of its proper divisors (1).

1052442134243 is an equidigital number, since it uses as much as digits as its factorization.

1052442134243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 92160, while the sum is 35.

Adding to 1052442134243 its reverse (3424312442501), we get a palindrome (4476754576744).

The spelling of 1052442134243 in words is "one trillion, fifty-two billion, four hundred forty-two million, one hundred thirty-four thousand, two hundred forty-three".