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10525817108993 is a prime number
BaseRepresentation
bin1001100100101011101110…
…0101101111101000000001
31101021020222021212222200212
42121022323211233220001
52334423333134441433
634215254342323505
72134315363130204
oct231127345575001
941236867788625
1010525817108993
113398a7939462a
12121bb82a29595
135b4770ba2c44
1428564903993b
15133c0234ed48
hex992bb96fa01

10525817108993 has 2 divisors, whose sum is σ = 10525817108994. Its totient is φ = 10525817108992.

The previous prime is 10525817108969. The next prime is 10525817109011. The reversal of 10525817108993 is 39980171852501.

10525817108993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9829874079169 + 695943029824 = 3135263^2 + 834232^2 .

It is a cyclic number.

It is not a de Polignac number, because 10525817108993 - 210 = 10525817107969 is a prime.

It is a super-2 number, since 2×105258171089932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10525817108903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5262908554496 + 5262908554497.

It is an arithmetic number, because the mean of its divisors is an integer number (5262908554497).

Almost surely, 210525817108993 is an apocalyptic number.

It is an amenable number.

10525817108993 is a deficient number, since it is larger than the sum of its proper divisors (1).

10525817108993 is an equidigital number, since it uses as much as digits as its factorization.

10525817108993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5443200, while the sum is 59.

The spelling of 10525817108993 in words is "ten trillion, five hundred twenty-five billion, eight hundred seventeen million, one hundred eight thousand, nine hundred ninety-three".