Base | Representation |
---|---|
bin | 11110101001010111110… |
… | …10111100110011111111 |
3 | 10201122222122112120002011 |
4 | 33110223322330303333 |
5 | 114223022442024442 |
6 | 2123424315112051 |
7 | 136035263065522 |
oct | 17245372746377 |
9 | 3648878476064 |
10 | 1053003861247 |
11 | 3766382563a8 |
12 | 1500b4a42627 |
13 | 783b4472450 |
14 | 38d73aa6bb9 |
15 | 1c5cebb4117 |
hex | f52bebccff |
1053003861247 has 32 divisors (see below), whose sum is σ = 1175491215360. Its totient is φ = 937274405760.
The previous prime is 1053003861187. The next prime is 1053003861263. The reversal of 1053003861247 is 7421683003501.
It is not a de Polignac number, because 1053003861247 - 235 = 1018644122879 is a prime.
It is a super-4 number, since 4×10530038612474 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1053003861647) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7813122 + ... + 7946752.
It is an arithmetic number, because the mean of its divisors is an integer number (36734100480).
Almost surely, 21053003861247 is an apocalyptic number.
1053003861247 is a deficient number, since it is larger than the sum of its proper divisors (122487354113).
1053003861247 is a wasteful number, since it uses less digits than its factorization.
1053003861247 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 133903.
The product of its (nonzero) digits is 120960, while the sum is 40.
Adding to 1053003861247 its reverse (7421683003501), we get a palindrome (8474686864748).
The spelling of 1053003861247 in words is "one trillion, fifty-three billion, three million, eight hundred sixty-one thousand, two hundred forty-seven".
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