Base | Representation |
---|---|
bin | 110001000010011111… |
… | …0101100100111101011 |
3 | 101001211020210122121202 |
4 | 1202010332230213223 |
5 | 3211133410241212 |
6 | 120213455554415 |
7 | 10415454204263 |
oct | 1420476544753 |
9 | 331736718552 |
10 | 105310243307 |
11 | 40730983535 |
12 | 184b022ba0b |
13 | 9c13a14649 |
14 | 51504007a3 |
15 | 2b155250c2 |
hex | 1884fac9eb |
105310243307 has 2 divisors, whose sum is σ = 105310243308. Its totient is φ = 105310243306.
The previous prime is 105310243237. The next prime is 105310243321. The reversal of 105310243307 is 703342013501.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 105310243307 - 228 = 105041807851 is a prime.
It is a super-2 number, since 2×1053102433072 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 105310243307.
It is not a weakly prime, because it can be changed into another prime (105010243307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52655121653 + 52655121654.
It is an arithmetic number, because the mean of its divisors is an integer number (52655121654).
Almost surely, 2105310243307 is an apocalyptic number.
105310243307 is a deficient number, since it is larger than the sum of its proper divisors (1).
105310243307 is an equidigital number, since it uses as much as digits as its factorization.
105310243307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 29.
Adding to 105310243307 its reverse (703342013501), we get a palindrome (808652256808).
The spelling of 105310243307 in words is "one hundred five billion, three hundred ten million, two hundred forty-three thousand, three hundred seven".
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