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1053167048737 is a prime number
BaseRepresentation
bin11110101001101011010…
…01011101100000100001
310201200102000121100020021
433110311221131200201
5114223341231024422
62123452424513441
7136042314132016
oct17246551354041
93650360540207
101053167048737
113767113855a1
1215013b61b881
137840c20a9ab
1438d8b62570d
151c5de19adc7
hexf535a5d821

1053167048737 has 2 divisors, whose sum is σ = 1053167048738. Its totient is φ = 1053167048736.

The previous prime is 1053167048707. The next prime is 1053167048753. The reversal of 1053167048737 is 7378407613501.

1053167048737 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 670431802401 + 382735246336 = 818799^2 + 618656^2 .

It is an emirp because it is prime and its reverse (7378407613501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1053167048737 - 211 = 1053167046689 is a prime.

It is a super-2 number, since 2×10531670487372 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1053167048707) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526583524368 + 526583524369.

It is an arithmetic number, because the mean of its divisors is an integer number (526583524369).

Almost surely, 21053167048737 is an apocalyptic number.

It is an amenable number.

1053167048737 is a deficient number, since it is larger than the sum of its proper divisors (1).

1053167048737 is an equidigital number, since it uses as much as digits as its factorization.

1053167048737 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2963520, while the sum is 52.

The spelling of 1053167048737 in words is "one trillion, fifty-three billion, one hundred sixty-seven million, forty-eight thousand, seven hundred thirty-seven".