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10533000405423 = 33511000135141
BaseRepresentation
bin1001100101000110011110…
…1111110110000110101111
31101021221111220112020220210
42121101213233312012233
52340033041100433143
634222443225313503
72134661366134326
oct231214757660657
941257456466823
1010533000405423
1133a1025152551
121221448635893
135b53471652c2
14285b2b06b0bd
15133ec2cc4033
hex99467bf61af

10533000405423 has 4 divisors (see below), whose sum is σ = 14044000540568. Its totient is φ = 7022000270280.

The previous prime is 10533000405413. The next prime is 10533000405463. The reversal of 10533000405423 is 32450400033501.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 10533000405423 - 26 = 10533000405359 is a prime.

It is a super-3 number, since 3×105330004054233 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10533000405413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1755500067568 + ... + 1755500067573.

It is an arithmetic number, because the mean of its divisors is an integer number (3511000135142).

Almost surely, 210533000405423 is an apocalyptic number.

10533000405423 is a deficient number, since it is larger than the sum of its proper divisors (3511000135145).

10533000405423 is an equidigital number, since it uses as much as digits as its factorization.

10533000405423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3511000135144.

The product of its (nonzero) digits is 21600, while the sum is 30.

Adding to 10533000405423 its reverse (32450400033501), we get a palindrome (42983400438924).

The spelling of 10533000405423 in words is "ten trillion, five hundred thirty-three billion, four hundred five thousand, four hundred twenty-three".

Divisors: 1 3 3511000135141 10533000405423