Base | Representation |
---|---|
bin | 11110101001111100110… |
… | …00010010111110100101 |
3 | 10201200210020021002002111 |
4 | 33110332120102332211 |
5 | 114224141231402401 |
6 | 2123515140441021 |
7 | 136046043254140 |
oct | 17247630227645 |
9 | 3650706232074 |
10 | 1053313544101 |
11 | 376787043745 |
12 | 1501806a9171 |
13 | 78433680640 |
14 | 38da2c7b057 |
15 | 1c5ebe86e51 |
hex | f53e612fa5 |
1053313544101 has 32 divisors (see below), whose sum is σ = 1301050032128. Its totient is φ = 830394452160.
The previous prime is 1053313544099. The next prime is 1053313544111. The reversal of 1053313544101 is 1014453133501.
It is not a de Polignac number, because 1053313544101 - 21 = 1053313544099 is a prime.
It is a super-2 number, since 2×10533135441012 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1053313544111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 128589916 + ... + 128598106.
It is an arithmetic number, because the mean of its divisors is an integer number (40657813504).
Almost surely, 21053313544101 is an apocalyptic number.
It is an amenable number.
1053313544101 is a deficient number, since it is larger than the sum of its proper divisors (247736488027).
1053313544101 is a wasteful number, since it uses less digits than its factorization.
1053313544101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13121.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 1053313544101 its reverse (1014453133501), we get a palindrome (2067766677602).
The spelling of 1053313544101 in words is "one trillion, fifty-three billion, three hundred thirteen million, five hundred forty-four thousand, one hundred one".
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