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105340214151 = 341300496471
BaseRepresentation
bin110001000011011000…
…1000001101110000111
3101001220100012022220000
41202012301001232013
53211214043323101
6120220450212343
710416300021654
oct1420661015607
9331810168800
10105340214151
1140746894027
12184ba2840b3
139c19ca9283
1451543a2c2b
152b17e95486
hex1886c41b87

105340214151 has 10 divisors (see below), whose sum is σ = 157360073112. Its totient is φ = 70226809380.

The previous prime is 105340214149. The next prime is 105340214227. The reversal of 105340214151 is 151412043501.

105340214151 is a `hidden beast` number, since 105 + 3 + 402 + 1 + 4 + 151 = 666.

It is not a de Polignac number, because 105340214151 - 21 = 105340214149 is a prime.

It is a super-2 number, since 2×1053402141512 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (105340214101) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 650248155 + ... + 650248316.

Almost surely, 2105340214151 is an apocalyptic number.

105340214151 is a deficient number, since it is larger than the sum of its proper divisors (52019858961).

105340214151 is an equidigital number, since it uses as much as digits as its factorization.

105340214151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1300496483 (or 1300496474 counting only the distinct ones).

The product of its (nonzero) digits is 2400, while the sum is 27.

Adding to 105340214151 its reverse (151412043501), we get a palindrome (256752257652).

The spelling of 105340214151 in words is "one hundred five billion, three hundred forty million, two hundred fourteen thousand, one hundred fifty-one".

Divisors: 1 3 9 27 81 1300496471 3901489413 11704468239 35113404717 105340214151