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1053444500483 is a prime number
BaseRepresentation
bin11110101010001100010…
…11110110110000000011
310201201010100200100110212
433111012023312300003
5114224423243003413
62123540135344335
7136052223340154
oct17250613666003
93651110610425
101053444500483
11376843a59161
121501b85220ab
137845484251b
1438db640992b
151c608703ca8
hexf5462f6c03

1053444500483 has 2 divisors, whose sum is σ = 1053444500484. Its totient is φ = 1053444500482.

The previous prime is 1053444500393. The next prime is 1053444500533. The reversal of 1053444500483 is 3840054443501.

1053444500483 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1053444500483 - 212 = 1053444496387 is a prime.

It is a super-2 number, since 2×10534445004832 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1053444500483.

It is not a weakly prime, because it can be changed into another prime (1053444500083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526722250241 + 526722250242.

It is an arithmetic number, because the mean of its divisors is an integer number (526722250242).

Almost surely, 21053444500483 is an apocalyptic number.

1053444500483 is a deficient number, since it is larger than the sum of its proper divisors (1).

1053444500483 is an equidigital number, since it uses as much as digits as its factorization.

1053444500483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 460800, while the sum is 41.

Adding to 1053444500483 its reverse (3840054443501), we get a palindrome (4893498943984).

The spelling of 1053444500483 in words is "one trillion, fifty-three billion, four hundred forty-four million, five hundred thousand, four hundred eighty-three".