Base | Representation |
---|---|
bin | 11110101010010000000… |
… | …01100101001010101111 |
3 | 10201201012111202020202211 |
4 | 33111020001211022233 |
5 | 114230004143031310 |
6 | 2123543201031251 |
7 | 136053046552636 |
oct | 17251001451257 |
9 | 3651174666684 |
10 | 1053475361455 |
11 | 37685a4174a0 |
12 | 150206925527 |
13 | 7845b05935a |
14 | 38dba56051d |
15 | 1c60b29cc8a |
hex | f5480652af |
1053475361455 has 32 divisors (see below), whose sum is σ = 1458768890880. Its totient is φ = 722813287680.
The previous prime is 1053475361447. The next prime is 1053475361467. The reversal of 1053475361455 is 5541635743501.
It is not a de Polignac number, because 1053475361455 - 23 = 1053475361447 is a prime.
It is a super-2 number, since 2×10534753614552 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1053475361399 and 1053475361408.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5611675 + ... + 5796364.
It is an arithmetic number, because the mean of its divisors is an integer number (45586527840).
Almost surely, 21053475361455 is an apocalyptic number.
1053475361455 is a deficient number, since it is larger than the sum of its proper divisors (405293529425).
1053475361455 is a wasteful number, since it uses less digits than its factorization.
1053475361455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11408151.
The product of its (nonzero) digits is 3780000, while the sum is 49.
The spelling of 1053475361455 in words is "one trillion, fifty-three billion, four hundred seventy-five million, three hundred sixty-one thousand, four hundred fifty-five".
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